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(F)=-F^2+60F
We move all terms to the left:
(F)-(-F^2+60F)=0
We get rid of parentheses
F^2-60F+F=0
We add all the numbers together, and all the variables
F^2-59F=0
a = 1; b = -59; c = 0;
Δ = b2-4ac
Δ = -592-4·1·0
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-59}{2*1}=\frac{0}{2} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+59}{2*1}=\frac{118}{2} =59 $
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